$x^2-4x-2y+5=0$
$tan\:\left(x-180\right)=tan\:x$
$3x+5\le10$
$3xy+5xyz$
$-199+-325$
$\int_{-1}^{\infty}\left(\frac{x+3}{x^2+4x+4}\right)dx$
$\left(6x^{\left(\frac{1}{4}\right)}\right)\left(4x^{\left(\frac{1}{2}\right)}\right)$
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