$\frac{dy}{dx}=\cos\left(2x\right)-\sin\left(x\right)$

$\frac{d}{dx}\left(y=x\left(ln8t\right)^2\right)$

$\frac{\left(\sec\left(x^3+x^2\right)\right)^4}{\cos\left(x\right)}$

$\int ln\cdot\left(2x+1\right)\:dx$

$\frac{dy}{dt}=te^{-y}$

$\:\int\frac{\:2x^2-1}{x^3-x}dx$

$\left(6m-2n\right)^2$