$x^2+18x+1=0$
$\frac{d}{dx}\left(5e^{4x}\right)$
$\left(4x-8\right)^2$
$\left(4x^2-9\right)\left(2x+3\right)$
$\frac{2x^4.3x^4}{3x^2}$
$\frac{169m^6-16n^6}{13m^3+4n^3}$
$\lim_{x\to\infty}\left(\frac{6x^2+4x}{e^x\:+\:2}\right)$
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