$tan^2x+sec^2x=3$
$\frac{dy}{dx}=-x\cos\left(x\right)+\sin\left(x\right)$
$4x^2-16x+3$
$5.7\cdot10^4$
$\frac{1-\sin\left(x\right)}{\cos\left(x\right)}-\sec\left(x\right)-\tan\left(x\right)$
$\frac{x+6}{3}-\frac{x+8}{5}=0$
$18a-14a=12$
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