$\:2b^4h-3b^3+7by^2h^2\:$
$1-csc^2\left(x\right)=cot^2\left(x\right)$
$\left(-10\right)\cdot17$
$\frac{x^3+5x-1}{x+3}$
$x2+5y-4;\:x=2;\:y=3$
$\lim_{x\to0}\left(\frac{\sin\left(6x^{12}\right)}{2x^{12}}\right)$
$6^{x+3}=-1$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!