$\int-4\ln\left(x\right)^2dx$
$49-28a^3+4a^6$
$\lim_{x\to-\infty}\left(2x^3+5x^2+3\right)$
$\left(84\right)-\left(-16\right)$
$\frac{1}{2}\left(1-cos\left(2x\right)\right)$
$\left(4x+2\right)\:\left(x-5\right)$
$8b^2+7b-1$
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