$\left(2a\right)+\left(3b\right)^4$
$x2-6x+32$
$\frac{d}{dx\:}c$
$\left(\frac{4xy}{y^6}\right)^3$
$\frac{1}{9}\left(3\right)^3+3-\frac{1}{9}\left(2\right)^3+2$
$25+60:3-6\cdot\left(3+11\right):7+3:\left(2-1\right)$
$\frac{5^8}{5^5}$
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