$x^2+4x-18=0$
$\frac{4}{x+2\:}\:\frac{3}{x-1}$
$\left(a^3-2b\right)^3$
$\lim_{x\to0}\left(\frac{\tan\left(2x\right)}{\sin\left(x\right)}\right)^{3x+6}$
$\left(-2\right)^3-\left(-3\right)^2$
$\left(5x^3y\right)^2$
$2n\left(8\right)-1$
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