$\left(b^{-\frac{4}{5}}\right)\left(b^{\frac{5}{6}}\right)$
$a^4-3a+5;\:a=-3$
$\left(2x-y\right)\left(z+4y\right)$
$\left(-7\right)^2-\left(-5\right)^2+\left(-2\right)^3-\left(-6\right)^2+4^2$
$32+10\cdot5$
$\int\left(y+2\right)^3dx$
$\frac{6^5\cdot6}{6^5}$
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