$\frac{dy}{dt}=\frac{\left(2y\right)}{t+1}$
$\frac{\sqrt[3]{\left(y+x\right)^2}-\sqrt[3]{y^2}}{x}$
$5b^2-3b$
$\sin\left(x\right)\tan\left(ydx\right)-\frac{dy}{\sin\left(x\right)}=0$
$3x+5y=0$
$\left(2x^2+y^2\right)dx+\left(x^2-2xy\right)dy=0$
$x^2+18x+1=1$
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