$\int_2^4\left(3x^2+2x+6\right)dx$
$-3+4-6-7-1-8+5-4-7$
$4+1-7+2+1-1+8$
$\frac{dy}{dx}-cot\left(x\right)y=sen\left(x\right)cos\left(x\right)y^3$
$\frac{dy}{dx}\left(x\right)=\frac{1}{3}.\frac{-4x+1}{y\left(x^2\right)}$
$5\cdot14$
$x+y+z=1$
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