$x\sin^2y\frac{dy}{dx}=\left(x+1\right)^2$
$\int\:\frac{5x+3}{\sqrt{x}}dx$
$\sin\left(2x\right)-\tan\left(x\right)=\tan\left(x\right)\cos\left(ax\right)$
$x^3-2x^2-11x+12$
$y'\:+\:2y\:=\:5x+\:5$
$2\cdot3\cdot4:2\cdot5$
$\frac{27x^6+8y^1}{3x^2+2y^5}$
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