$x^3+y+3x^2y=y$
$\left(4a^2b^2-3ab^4\right)^3$
$xy+4y=x^{-3}e^x$
$\frac{d^3}{dx^3}\left(12x^4+cotx\right)$
$\log\left(y^2+4y+14\right)=\log\left(-3y+22\right)$
$196 b ^ { 2 } - 121$
$y'\:=\:\left(-x\:-\:1\right)\:y^3$
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