$\frac{\left(n^2+4\right)}{8n-2n^3}$
$\frac{1}{2}a-\frac{2}{3}b-\left(\frac{3}{4}q-\frac{4}{3}b\right)$
$sec^2x\:+\:csc^2x\:=\:\frac{1}{sen^2x\:\cdot\:cos^2x}\:$
$25x^2-45x+18$
$\frac{4x^2-16}{x-2}$
$-6.5\:+\:-3.5$
$-25+\frac{14}{7}$
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