$\int_1^{\infty}\left(\frac{21}{221x+110+110x^2}\right)dx$

$x^5-10x^4+21x^3+64x^2-268x+240$

$4\left(x+2\right)-3\left(x-5\right)^2\ge10$

$\left(\frac{2}{3}a-\frac{1}{3}b\right)^3$

$\left(3x^2\right)\left(x+3\right)$

$\left(40\right)-\left(-10\right)$

$\lim_{x\to-\infty}\left(\frac{3-x^3}{x^2}\right)$