$\left(2x^2-3x-4\right)-\left(3x^2-4x+2\right)$

$2\ln\left(x-2\right)=\ln\left(16-x\right)$

$\frac{\left(2a^2+2ab\right)}{3a^2b}$

$\lim_{x\to-2}\left(\frac{5x\left(3+\sqrt{7-x}\right)}{x^3+8}\right)$

$-8-\left|-3\right|$

$3x^3+375$

$\cos\left(x\right)\left(\sin^2\left(x\right)-\cos^2\left(x\right)\right)\sec\left(x\right)+\cos^2\left(x\right)$