$\lim_{x\to2}\left(\left(\tan\left(x-2\right)\cdot\left(\sqrt{x+2}-2\right)\right)\right)$
$\lim_{x\to-\infty}\frac{5^x}{3^x+2^x}.$
$\left(4t+1\right)\left(3t+2\right)$
$\left(6.7\right)\:-18\::\:\left(-6\right)$
$\left(\frac{2}{3}-3x\right)^2$
$a+2a-2a$
$\left(0-2\right)^2-3$
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