$8=9-v$
$\frac{\frac{sin\left(a\right)^2+cos\left(a\right)^2}{cos\left(a\right)}}{sin\left(a\right)}=sec\left(a\right)csc\left(a\right)$
$\left(2y\:-\:1\right)\left(2y\:-\:3\right)$
$\left(5a^3+3b^3\right)\left(5a^3-3b^3\right)$
$\frac{3}{2}x^2-5x+\frac{1}{3}-\frac{9}{4}x^2+\frac{11}{2}x-3$
$3.4ab-5.6ab$
$-18x+9-23x$
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