$\int\frac{1}{\left(x+1\right)+\left(x+2\right)\left(x+3\right)}dx$

$x^2+9<0$

$\left(\frac{3}{2}xy^3+\frac{1}{4}z\right)\left(\frac{3}{2}xy^3-\frac{1}{4}z\right)$

$\frac{tanx}{secx-1}=secx+1$

$\left(x^{10}+3\right)\left(x^{10}-2\right)$

$\frac{x^3-4x^2}{x^2-16}\:$

$202\cdot3$