$x^2+y^2\:para\:x=1;\:y=3$
$104+3\left(90.50\right)$
$-3a+8=5a+24$
$\frac{2x^2-4x+10}{x+1}$
$\sin\left(x\right)^2=1-\cos\left(x\right)$
$\frac{xdx}{x^2+1}=-\frac{\cos\left(y\right)}{\sin\left(y\right)}dy$
$r+z+x+z$
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