$\left(a^x-b^x+1\right)^3$
$\cos\left(y\right)\sec\left(y\right)=1$
$\lim_{x\to\infty}\left(\frac{x+1}{x^3+7x}\right)$
$\frac{3x^2}{-9x^5}$
$\lim_{x\to\infty}\left(-\frac{1}{3}\right)^x$
$3s^2+-7s^2+-5s^2$
$sec^2x\:dy\:+csc\:dx=0$
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