$5\cdot\frac{4}{5}$
$2\pi^2+4\pi^2y$
$\left(3x\right)^4\left(6x\right)^3\left(8x\right)^2$
$\lim_{x\to0}\left(\frac{1-x^2}{\sqrt[3]{x}}\right)$
$-15:-9$
$x^6+6x^3+9$
$-\frac{9}{8}n.\frac{4}{3}m^2$
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