$\lim_{x\to\infty}\left(\frac{4xe^x}{x^2-2}\right)$
$\int\left(\frac{1}{\sqrt{x^2-5x+4}}\right)dx$
$-\frac{-8}{-4}$
$\left(3x+1\right)\left(2x+1\right)$
$\lim_{x\to5}\left(\frac{\left|x-5\right|}{x-5}\right)$
$\left(4a^2b+5b\right).\left(4a^2b-5b\right)$
$x+5=6$
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