$f\left(x\right)=\left(5x^3+4x^2\right)^2$
$\left(\frac{1}{x^5}\right)^{\frac{-3}{5}}$
$8\sin\left(x\right)=2$
$\left(3x^4-5\right)^3$
$+1+6-\left(-3\right)$
$m^2+n^2=70$
$\frac{x^2-2x}{\sqrt[20]{x-2}}$
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