$x^2+13x+36>0$
$\tan^4\theta+2\tan^2\theta+1=\sec^4\theta$
$-12+0x+8+0x$
$-4.39-\left(8.76\right)$
$\frac{d}{dx}7x^2+2y^3$
$\sqrt{x^2+\left(2\right)^2}$
$\frac{x^4}{8-x^3}$
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