$x^2+24x+80$

$\frac{sen\left(2x+3\right)}{y}dx+\frac{e^{4y^2}}{x+5}dy=0$

$x^2-5x+6\ge x+5$

$f\left(x\right)=x^2+2x-1\:tienda\:\frac{1}{4}$

$c\left(16x+14\right)$

$\left(\frac{2}{2}\sqrt{4-2^2}+\frac{4}{2}\arcsin\frac{2}{3}\right)$

$\frac{dy}{dx}\left(e^{-x}+e^x\right)-y^2=0\:;\:y\left(1\right)=1$