$\frac{dy}{dx}=\frac{1}{x^2-4}$
$\frac{8\left(x+1\right)^3}{\left(x-1\right)^5}$
$\lim\:_{x\to\:\infty\:}\left(arctan\left(\frac{x^2+\sqrt{x}}{\sqrt[3]{x}-\sqrt{3x^2}}\right)\right)$
$0=-3$
$\left(x-\frac{17}{6}\right)^2$
$183+80.93$
$\left(a^6\right)^2a^7$
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