$\left(\left(-9\right)+\left(-3\right)\right)\left(6\right)$
$a^2-100b^2$
$\left(3+y\right)\left(3+n\right)$
$\left(x^3+\frac{1}{3}\right)\left(x^3-\frac{3}{4}\right)$
$-7,8+0,6$
$3x^2+2\times\:\:5x$
$2401\left(6\right)$
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