$400a^{10}+40a^5+1$
$3y^2+5y=12$
$\lim_{x\to0}5x$
$-\left(-8\right)-\left(-8\right)-\left(-8\right)-\left(-8\right)-\left(-8\right)$
$15m^2+11m-14$
$x^2+8x+10$
$y'+y=b^2$
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