$y'\:=xy+9x$
$7x>-14$
$\frac{a^7}{a^3}$
$\:y\:=\:\left(x\:-\:3\right)\left(x\:+\:7\right)$
$-6+\left(-1\right)^4$
$2x^2-7x+4=0$
$\int\left(\frac{1+tan^2x}{sec^2x}\right)dx$
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