$4y'-6e^xy=0$
$25x^2+40x-27$
$ln\left(\frac{\left(7+y\right)}{8-y}\right)$
$cos\left(3x\right)=\cos\left(x\right)^3-3\sin\left(x\right)^2\cos\left(x\right)$
$\frac{\left(\sin a-\cos a\right)\left(1+\sin a\cos a\right)}{\cos^3a}=\tan^3a-1$
$2x\:+\:36\:=\:2x\:+\:24$
$\int14xe^{12x}dx$
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