$\int\frac{-18x^2}{x^3+4}dx$

$\frac{3x^3+2x^2-5x-4}{x+1}$

$\left(6cos\:x\:-\:8sin\:x\right)^2+\left(8\:cos\:x\:+\:6\:sin\:x\right)^2=100$

$1.6667^3$

$\lim_{x\to\infty}\frac{\sqrt{x^2+9}}{x^2+5}$

$-3+\left(4-\left(2\right)\left(5\right)\right)+\left(3+2\right)\cdot7+5\left(-1\right)+3\cdot8$

$6x^2-2x^2+7x-4x$