$9\left(x-y\right)^2+12\left(x-y\right)\left(x+y\right)+4\left(x+y^2\right)$
$0\:\left(-10\right)\left(+3\right)\left(-2\right)\:$
$\int\left(\frac{x^6+x^2}{x^3}\right)dx$
$6\left(-9f\:+\:7\right)$
$\int6x\left(x^2+1\right)^2dx$
$\left(5m-6\right)^2$
$9x^8+6x^4+1$
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