$\int\frac{x^2}{\left(x^2+4\right)\left(x^2+4\right)}dx$
$\frac{dx}{dy}=\frac{x}{y^2}$
$\frac{1}{25}x^6+\frac{6}{5}x^4y+9x^2y^2$
$8n^2+5n^3+2n-3n^2-3n-4n^3$
$5\left(x+8\right)$
$x\:\frac{dy}{dx}-4y=x^6e^x$
$x^2y-3x^2z+7x^2$
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