$10^1\cdot3^2$
$-7\left(-4\right)\left(27\right)$
$\left(x+y+1\right)\left(x+3\right)$
$secy\left(1+cot^2y\right)$
$\int\frac{\left(32\cdot ln\left(4x\right)\right)}{x^5}\cdot dx$
$2a^2+4a^3+3a^3$
$\frac{d}{dx}\left(y^5+xy^2=24\right)$
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