$-3x^3+10x^3-4x^3+6x^3-x^3$
$9x^2+30+25\left(3x+5\right)^2$
$3\:a^2\:b^3-\:40\:d;\:a=2\:;b=3;\:d=\frac{1}{2}$
$\ln\left(3x^3-4\right)\left(9x^2-4\right)$
$\left(x^3-3x^2-3x-1\right)\left(x-1\right)$
$\left(-5\right)^{2}\left(-6\right)^{\left(-5+5\right)}+\left(-3\right)+\left(+\right)-\left(+3\right)\left(-2\right)$
$-2\left(-c-12\right)=-2c-12$
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