$\left(10+4\right):\left(10-3\right)$
$4x^2-4xy^2+y^4$
$\left(-1\right)^2+\left(-1\right)^3-1^4+1^5$
$b-1>2b+6$
$\frac{dy}{dx}+\frac{1}{20}y=0.75$
$\left(3^{-7}\right)^{-1}$
$\left(m^3+2\right)\left(m^3+3\right)$
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