$\:\frac{1}{x^3+4x}$
$\frac{dy}{dx}=18x^2$
$\int\left(2x-5\right)^2dx$
$10-\left(-2-3\right)$
$16^{2^{-1}}$
$2y=x+1$
$4x^3-26x-12$
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