$25a^2+49^4-2$
$\frac{14xyz}{-6}$
$\sqrt[3]{\frac{s^{-3}}{s^{-4}}}$
$\left(\sqrt{\tan\left(4x\right)}\right)^2$
$\frac{\sin^4\left(x\right)-\cos^4\left(x\right)}{\sin\left(x\right)-\cos\left(x\right)}$
$b2+3b+7$
$x^2-14x-1=0$
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