$\frac{\sin^2\left(x\right)-2\sin\left(x\right)+1}{2\sin\left(x\right)+1}=\sin\left(x\right)-1$

$\left(n^2+4mn\right)\left(n^2+4mn\right)$

$\left|-1-6\right|$

$\left(3x^2\right)^536x^5$

$-0.5x^2+x-3.245$

$\frac{d}{dx}\left(\:x^3+y^3=6x^2y-9+2^{\frac{3}{2}}\right)$

$4\sin\left(3x\right)=2$