$\frac{\tan\left(1\right)+\cos\left(1\right)}{\sin\left(1\right)}=\sec\left(1\right)+\cot\left(1\right)$
$\frac{2x+21}{2x^2+9x-5}$
$p\left(x\right)=5\sqrt{6}x\:2+3x\:-6\sqrt{6}$
$y'+2y=8$
$\frac{6x-48}{5x^2-320}$
$\sqrt{25-9}-2\left(5-3\right)+2$
$\left(2x-\frac{1}{3}x^2\right)\left(2x+\frac{1}{3x^2}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!