$\lim_{x\to\infty}\left(\frac{2e^x+x^2}{e^x+5}\right)$
$y=\left(3x+1\right)\left(4x-2\right)$
$\frac{dy}{dx}=\sqrt{4+2y}$
$\left(x^2-5\right)\left(x^4+5x^2+25\right)$
$\left(4x^2+2x\right)+\left(2x^2+x\right)$
$x\left(\ln x-\ln y\right)dy-ydx=0$
$-\frac{24}{3}$
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