$\lim_{x\to\infty}\left(\frac{\left(3^x+6^x\right)}{5}\right)^{\left(\frac{1}{t}\right)}$

$\frac{1\:+\:cos\:v\:}{1\:-\:cos\:v\:}=\:\frac{sec\:v\:+\:1}{sec\:v\:-1}$

$\left(2x+3y\right)dx+\left(y+3x\right)dy\:=\:0$

$\int\left(\frac{cos\left(6x+2\right)}{sin^2\left(6x+2\right)}\right)dx$

$\lim_{x\to-\infty}\left(\frac{\ln\left(x^4+3\right)}{13x+1}\right)$

$-8\cdot\left(-22\right)$

$90=\left(3x-20\right)\left(7x+10\right)$