$\sqrt{\frac{5}{4}}x^2\left(5\right)$
$\frac{dy}{dx}\left(y\right)\:\frac{\left(x-7\right)^3}{\left(x-5\right)^4}$
$\left(u^{-2}u^3\right)^{-3}$
$\left(a+13\right)\left(3a-13\right)$
$\left(5x-10x^2\right)^2$
$\frac{y^{15}}{y^5}$
$27\left(-3\right)$
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