$\frac{x^4}{16}-\frac{y^2}{9}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:$
$-12+5x<-x$
$1312^3$
$x+3>4,1$
$\frac{dx}{dt}\left(\frac{1}{t}-1\right)x=4e^t$
$\frac{d^2y}{dx^2}+4=0$
$9x^2-36x+4y^2=0$
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