$7x+12=40$
$113\cdot15$
$\frac{d}{dx}13^x$
$\frac{dy}{dx}=\frac{2+\sqrt{x}}{7+\sqrt{y}}$
$\lim_{x\to0}\left(\frac{1}{logx}log\cot x\right)$
$\left(3x^2+5x-12\right)-2\left(x^2+4x+9\right)$
$\left(3x^2+1\right)^4$
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