$y=\frac{2}{2\sqrt{2x}}+\frac{3}{3\sqrt[3]{3x^2}}$
$\int_{-3}^3\left(x^{-2}\right)dx$
$\left(x-11\right)\left(x+2\right)$
$4\left(b+4\right)$
$\left(6xy+3x^4\right)^2$
$\lim_{x\to0}\left(\frac{sin\left(x+3\right)}{x^2-4x-21}\right)$
$4x^4+4x^2+4$
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