$\lim_{x\to0}\left(\frac{5x^2-3x}{9x^2+5}\right)$
$\sqrt{3}\csc\left(9x\right)-7=-5$
$x1=5$
$\frac{3x^4-5x^2+4x+12}{2x^2+x}$
$\frac{dz}{dx}=-x^3-\frac{z}{x}$
$\left(4x+1\right)\left(4x+9\right)$
$\lim_{x\to0}\frac{\left(tan\left(x\right)-x\right)}{x^3}$
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