$2\cos^2\left(\frac{x}{4}\right)-3\cos\left(\frac{x}{4}\right)=0$
$\lim_{x\to\infty}\left(\frac{ln\left(5^x-1\right)}{x+2}\right)$
$27+a^3b^9$
$x^4-10x^3+9$
$-2g^2-24g=-26$
$38,9-2,6$
$3-\left(4+2\right)$
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