$\left(\frac{1}{2}x^4+\frac{2}{6}x^3-\frac{4}{2}x^2+\frac{3}{8}x+0\right)+\left(-0x^4-\frac{2}{3}x^3-\frac{5}{3}x^2+\frac{1}{3}x-\frac{7}{3}\right)$

$\frac{d}{dx}\left(y^2+2y^1=x\right)$

$x^3-x^2-2x$

$\frac{x^4}{x^6}$

$tanx^2-3=0$

$-5y^2-3x-6x^2-4x$

$\frac{-13x^2y^2+7y^4+9xy^4}{2x^3-3y^4}$